check-balanced-string

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Algorithms

You are given a string <code>num</code> consisting of only digits. A string of digits is called balanced if the sum of the digits at even indices is equal to the sum of digits at odd indices.

Return <code>true</code> if <code>num</code> is balanced, otherwise return <code>false</code>.

&nbsp;
Example 1:

<div class="example-block">
Input: num = &quot;1234&quot;

Output: false

Explanation:

<ul>
	<li>The sum of digits at even indices is <code>1 + 3 == 4</code>, and the sum of digits at odd indices is <code>2 + 4 == 6</code>.</li>
	<li>Since 4 is not equal to 6, <code>num</code> is not balanced.</li>
</ul>
</div>

Example 2:

<div class="example-block">
Input: num = &quot;24123&quot;

Output: true

Explanation:

<ul>
	<li>The sum of digits at even indices is <code>2 + 1 + 3 == 6</code>, and the sum of digits at odd indices is <code>4 + 2 == 6</code>.</li>
	<li>Since both are equal the <code>num</code> is balanced.</li>
</ul>
</div>

&nbsp;
Constraints:

<ul>
	<li><code>2 &lt;= num.length &lt;= 100</code></li>
	<li><code>num</code> consists of digits only</li>
</ul>

isBalanced

Check Balanced String

Balanced Binary Tree

balanced-binary-tree

平衡二叉树

String

给你一个仅由数字 0 - 9 组成的字符串 <code>num</code>。如果偶数下标处的数字之和等于奇数下标处的数字之和，则认为该数字字符串是一个 平衡字符串。

如果 <code>num</code> 是一个 平衡字符串，则返回 <code>true</code>；否则，返回 <code>false</code>。

&nbsp;

示例 1：

<div class="example-block">
输入：num = "1234"

输出：false

解释：

<ul>
	<li>偶数下标处的数字之和为 <code>1 + 3 = 4</code>，奇数下标处的数字之和为 <code>2 + 4 = 6</code>。</li>
	<li>由于 4 不等于 6，<code>num</code> 不是平衡字符串。</li>
</ul>
</div>

示例 2：

<div class="example-block">
输入：num = "24123"

输出：true

解释：

<ul>
	<li>偶数下标处的数字之和为 <code>2 + 1 + 3 = 6</code>，奇数下标处的数字之和为 <code>4 + 2 = 6</code>。</li>
	<li>由于两者相等，<code>num</code> 是平衡字符串。</li>
</ul>
</div>

&nbsp;

提示：

<ul>
	<li><code>2 &lt;= num.length &lt;= 100</code></li>
	<li><code>num</code> 仅由数字 0 - 9 组成。</li>
</ul>