convert-binary-number-in-a-linked-list-to-integer

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Algorithms

Given <code>head</code> which is a reference node to a singly-linked list. The value of each node in the linked list is either <code>0</code> or <code>1</code>. The linked list holds the binary representation of a number.

Return the decimal value of the number in the linked list.

The most significant bit is at the head of the linked list.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/05/graph-1.png" style="width: 426px; height: 108px;" />
<pre>
Input: head = [1,0,1]
Output: 5
Explanation: (101) in base 2 = (5) in base 10
</pre>

Example 2:

<pre>
Input: head = [0]
Output: 0
</pre>

&nbsp;
Constraints:

<ul>
	<li>The Linked List is not empty.</li>
	<li>Number of nodes will not exceed <code>30</code>.</li>
	<li>Each node&#39;s value is either <code>0</code> or <code>1</code>.</li>
</ul>

第 167 场周赛

weekly-contest-167

getDecimalValue

中级工程师

Convert Binary Number in a Linked List to Integer

Linked List

Math

给你一个单链表的引用结点&nbsp;<code>head</code>。链表中每个结点的值不是 0 就是 1。已知此链表是一个整数数字的二进制表示形式。

请你返回该链表所表示数字的 十进制值 。

最高位 在链表的头部。

&nbsp;

示例 1：

<img alt="" src="https://assets.leetcode.cn/aliyun-lc-upload/uploads/2019/12/15/graph-1.png" style="height: 108px; width: 426px;" />

<pre>
输入：head = [1,0,1]
输出：5
解释：二进制数 (101) 转化为十进制数 (5)
</pre>

示例 2：

<pre>
输入：head = [0]
输出：0
</pre>

&nbsp;

提示：

<ul>
	<li>链表不为空。</li>
	<li>链表的结点总数不超过&nbsp;<code>30</code>。</li>
	<li>每个结点的值不是&nbsp;<code>0</code> 就是 <code>1</code>。</li>
</ul>