count-odd-numbers-in-an-interval-range

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Algorithms

Given two non-negative integers <code>low</code> and <code>high</code>. Return the count of odd numbers between <code>low</code> and <code>high</code>&nbsp;(inclusive).

&nbsp;
Example 1:

<pre>
Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].</pre>

Example 2:

<pre>
Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].</pre>

&nbsp;
Constraints:

<ul>
	<li><code>0 &lt;= low &lt;= high&nbsp;&lt;= 10^9</code></li>
</ul>

countOdds

Count Odd Numbers in an Interval Range

Check if Bitwise OR Has Trailing Zeros

check-if-bitwise-or-has-trailing-zeros

检查按位或是否存在尾随零

Math

给你两个非负整数&nbsp;<code>low</code> 和&nbsp;<code>high</code>&nbsp;。请你返回&nbsp;<code>low</code> 和&nbsp;<code>high</code>&nbsp;之间（包括二者）奇数的数目。

&nbsp;

示例 1：

<pre>输入：low = 3, high = 7
输出：3
解释：3 到 7 之间奇数数字为 [3,5,7] 。</pre>

示例 2：

<pre>输入：low = 8, high = 10
输出：1
解释：8 到 10 之间奇数数字为 [9] 。</pre>

&nbsp;

提示：

<ul>
	<li><code>0 &lt;= low &lt;= high&nbsp;&lt;= 10^9</code></li>
</ul>