count-of-matches-in-tournament

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Algorithms

You are given an integer <code>n</code>, the number of teams in a tournament that has strange rules:

<ul>
	<li>If the current number of teams is even, each team gets paired with another team. A total of <code>n / 2</code> matches are played, and <code>n / 2</code> teams advance to the next round.</li>
	<li>If the current number of teams is odd, one team randomly advances in the tournament, and the rest gets paired. A total of <code>(n - 1) / 2</code> matches are played, and <code>(n - 1) / 2 + 1</code> teams advance to the next round.</li>
</ul>

Return the number of matches played in the tournament until a winner is decided.

&nbsp;
Example 1:

<pre>
Input: n = 7
Output: 6
Explanation: Details of the tournament: 
- 1st Round: Teams = 7, Matches = 3, and 4 teams advance.
- 2nd Round: Teams = 4, Matches = 2, and 2 teams advance.
- 3rd Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 3 + 2 + 1 = 6.
</pre>

Example 2:

<pre>
Input: n = 14
Output: 13
Explanation: Details of the tournament:
- 1st Round: Teams = 14, Matches = 7, and 7 teams advance.
- 2nd Round: Teams = 7, Matches = 3, and 4 teams advance.
- 3rd Round: Teams = 4, Matches = 2, and 2 teams advance.
- 4th Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 7 + 3 + 2 + 1 = 13.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= n &lt;= 200</code></li>
</ul>

numberOfMatches

Count of Matches in Tournament

Count Distinct Numbers on Board

count-distinct-numbers-on-board

统计桌面上的不同数字

Math

Simulation

给你一个整数 <code>n</code> ，表示比赛中的队伍数。比赛遵循一种独特的赛制：

<ul>
	<li>如果当前队伍数是 偶数 ，那么每支队伍都会与另一支队伍配对。总共进行 <code>n / 2</code> 场比赛，且产生 <code>n / 2</code> 支队伍进入下一轮。</li>
	<li>如果当前队伍数为 奇数 ，那么将会随机轮空并晋级一支队伍，其余的队伍配对。总共进行 <code>(n - 1) / 2</code> 场比赛，且产生 <code>(n - 1) / 2 + 1</code> 支队伍进入下一轮。</li>
</ul>

返回在比赛中进行的配对次数，直到决出获胜队伍为止。

 

示例 1：

<pre>输入：n = 7
输出：6
解释：比赛详情：
- 第 1 轮：队伍数 = 7 ，配对次数 = 3 ，4 支队伍晋级。
- 第 2 轮：队伍数 = 4 ，配对次数 = 2 ，2 支队伍晋级。
- 第 3 轮：队伍数 = 2 ，配对次数 = 1 ，决出 1 支获胜队伍。
总配对次数 = 3 + 2 + 1 = 6
</pre>

示例 2：

<pre>输入：n = 14
输出：13
解释：比赛详情：
- 第 1 轮：队伍数 = 14 ，配对次数 = 7 ，7 支队伍晋级。
- 第 2 轮：队伍数 = 7 ，配对次数 = 3 ，4 支队伍晋级。 
- 第 3 轮：队伍数 = 4 ，配对次数 = 2 ，2 支队伍晋级。
- 第 4 轮：队伍数 = 2 ，配对次数 = 1 ，决出 1 支获胜队伍。
总配对次数 = 7 + 3 + 2 + 1 = 13
</pre>

 

提示：

<ul>
	<li><code>1 &lt;= n &lt;= 200</code></li>
</ul>