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JavaScript

Given an integer&nbsp;<code>n</code>,&nbsp;return a <code>counter</code> function. This <code>counter</code> function initially returns&nbsp;<code>n</code>&nbsp;and then returns 1 more than the previous value every subsequent time it is called (<code>n</code>, <code>n + 1</code>, <code>n + 2</code>, etc).

&nbsp;
Example 1:

<pre>
Input: 
n = 10 
[&quot;call&quot;,&quot;call&quot;,&quot;call&quot;]
Output: [10,11,12]
Explanation: 
counter() = 10 // The first time counter() is called, it returns n.
counter() = 11 // Returns 1 more than the previous time.
counter() = 12 // Returns 1 more than the previous time.
</pre>

Example 2:

<pre>
Input: 
n = -2
[&quot;call&quot;,&quot;call&quot;,&quot;call&quot;,&quot;call&quot;,&quot;call&quot;]
Output: [-2,-1,0,1,2]
Explanation: counter() initially returns -2. Then increases after each sebsequent call.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>-1000&nbsp;&lt;= n &lt;= 1000</code></li>
	<li><code>0 &lt;= calls.length &lt;= 1000</code></li>
	<li><code>calls[i] === &quot;call&quot;</code></li>
</ul>

createCounter

Counter

Memoize

memoize

记忆函数

Function Composition

function-composition

复合函数

Counter II

counter-ii

计数器 II

给定一个整型参数 <code>n</code>，请你编写并返回一个 <code>counter</code>&nbsp;函数。这个&nbsp;<code>counter</code>&nbsp;函数最初返回 <code>n</code>，每次调用它时会返回前一个值加 1 的值 ( <code>n</code> ,&nbsp; <code>n + 1</code> ,&nbsp; <code>n + 2</code> ，等等)。

&nbsp;

示例 1：

<pre>
输入：
n = 10 
["call","call","call"]
输出：[10,11,12]
解释：
counter() = 10 // 第一次调用 counter()，返回 n。
counter() = 11 // 返回上次调用的值加 1。
counter() = 12 // 返回上次调用的值加 1。
</pre>

示例 2：

<pre>
输入：
n = -2
["call","call","call","call","call"]
输出：[-2,-1,0,1,2]
解释：counter() 最初返回 -2。然后在每个后续调用后增加 1。
</pre>

&nbsp;

提示：

<ul>
	<li><code>-1000&nbsp;&lt;= n &lt;= 1000</code></li>
	<li><code>0 &lt;= calls.length &lt;= 1000</code></li>
	<li><code>calls[i] === "call"</code></li>
</ul>