find-the-smallest-divisor-given-a-threshold

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Algorithms

Given an array of integers <code>nums</code> and an integer <code>threshold</code>, we will choose a positive integer <code>divisor</code>, divide all the array by it, and sum the division&#39;s result. Find the smallest <code>divisor</code> such that the result mentioned above is less than or equal to <code>threshold</code>.

Each result of the division is rounded to the nearest integer greater than or equal to that element. (For example: <code>7/3 = 3</code> and <code>10/2 = 5</code>).

The test cases are generated so&nbsp;that there will be an answer.

&nbsp;
Example 1:

<pre>
Input: nums = [1,2,5,9], threshold = 6
Output: 5
Explanation: We can get a sum to 17 (1+2+5+9) if the divisor is 1. 
If the divisor is 4 we can get a sum of 7 (1+1+2+3) and if the divisor is 5 the sum will be 5 (1+1+1+2). 
</pre>

Example 2:

<pre>
Input: nums = [44,22,33,11,1], threshold = 5
Output: 44
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= nums.length &lt;= 5 * 104</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 106</code></li>
	<li><code>nums.length &lt;= threshold &lt;= 106</code></li>
</ul>

smallestDivisor

Find the Smallest Divisor Given a Threshold

Minimized Maximum of Products Distributed to Any Store

minimized-maximum-of-products-distributed-to-any-store

分配给商店的最多商品的最小值

Array

Binary Search

给你一个整数数组&nbsp;<code>nums</code> 和一个正整数&nbsp;<code>threshold</code> &nbsp;，你需要选择一个正整数作为除数，然后将数组里每个数都除以它，并对除法结果求和。

请你找出能够使上述结果小于等于阈值&nbsp;<code>threshold</code>&nbsp;的除数中 最小 的那个。

每个数除以除数后都向上取整，比方说 7/3 = 3 ， 10/2 = 5 。

题目保证一定有解。

&nbsp;

示例 1：

<pre>
输入：nums = [1,2,5,9], threshold = 6
输出：5
解释：如果除数为 1 ，我们可以得到和为 17 （1+2+5+9）。
如果除数为 4 ，我们可以得到和为 7 (1+1+2+3) 。如果除数为 5 ，和为 5 (1+1+1+2)。
</pre>

示例 2：

<pre>
输入：nums = [2,3,5,7,11], threshold = 11
输出：3
</pre>

示例 3：

<pre>
输入：nums = [19], threshold = 5
输出：4
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= nums.length &lt;= 5 * 10^4</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10^6</code></li>
	<li><code>nums.length &lt;=&nbsp;threshold &lt;= 10^6</code></li>
</ul>