generate-a-string-with-characters-that-have-odd-counts

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Algorithms

Given an&nbsp;integer <code>n</code>, return a string with <code>n</code>&nbsp;characters such that each character in such string occurs an odd number of times.

The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them. &nbsp;

&nbsp;
Example 1:

<pre>
Input: n = 4
Output: &quot;pppz&quot;
Explanation: &quot;pppz&quot; is a valid string since the character &#39;p&#39; occurs three times and the character &#39;z&#39; occurs once. Note that there are many other valid strings such as &quot;ohhh&quot; and &quot;love&quot;.
</pre>

Example 2:

<pre>
Input: n = 2
Output: &quot;xy&quot;
Explanation: &quot;xy&quot; is a valid string since the characters &#39;x&#39; and &#39;y&#39; occur once. Note that there are many other valid strings such as &quot;ag&quot; and &quot;ur&quot;.
</pre>

Example 3:

<pre>
Input: n = 7
Output: &quot;holasss&quot;
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= n &lt;= 500</code></li>
</ul>

generateTheString

Generate a String With Characters That Have Odd Counts

String

给你一个整数 <code>n</code>，请你返回一个含 <code>n</code> 个字符的字符串，其中每种字符在该字符串中都恰好出现 奇数次 。

返回的字符串必须只含小写英文字母。如果存在多个满足题目要求的字符串，则返回其中任意一个即可。

&nbsp;

示例 1：

<pre>输入：n = 4
输出：&quot;pppz&quot;
解释：&quot;pppz&quot; 是一个满足题目要求的字符串，因为 &#39;p&#39; 出现 3 次，且 &#39;z&#39; 出现 1 次。当然，还有很多其他字符串也满足题目要求，比如：&quot;ohhh&quot; 和 &quot;love&quot;。
</pre>

示例 2：

<pre>输入：n = 2
输出：&quot;xy&quot;
解释：&quot;xy&quot; 是一个满足题目要求的字符串，因为 &#39;x&#39; 和 &#39;y&#39; 各出现 1 次。当然，还有很多其他字符串也满足题目要求，比如：&quot;ag&quot; 和 &quot;ur&quot;。
</pre>

示例 3：

<pre>输入：n = 7
输出：&quot;holasss&quot;
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= n &lt;= 500</code></li>
</ul>