jewels-and-stones

java

python

python3

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oraclesql

csharp

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racket

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cangjie

Algorithms

You&#39;re given strings <code>jewels</code> representing the types of stones that are jewels, and <code>stones</code> representing the stones you have. Each character in <code>stones</code> is a type of stone you have. You want to know how many of the stones you have are also jewels.

Letters are case sensitive, so <code>&quot;a&quot;</code> is considered a different type of stone from <code>&quot;A&quot;</code>.

&nbsp;
Example 1:
<pre>Input: jewels = "aA", stones = "aAAbbbb"
Output: 3
</pre>Example 2:
<pre>Input: jewels = "z", stones = "ZZ"
Output: 0
</pre>
&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;=&nbsp;jewels.length, stones.length &lt;= 50</code></li>
	<li><code>jewels</code> and <code>stones</code> consist of only English letters.</li>
	<li>All the characters of&nbsp;<code>jewels</code> are unique.</li>
</ul>

numJewelsInStones

Jewels and Stones

Hash Table

String

&nbsp;给你一个字符串 <code>jewels</code>&nbsp;代表石头中宝石的类型，另有一个字符串 <code>stones</code> 代表你拥有的石头。&nbsp;<code>stones</code>&nbsp;中每个字符代表了一种你拥有的石头的类型，你想知道你拥有的石头中有多少是宝石。

字母区分大小写，因此 <code>"a"</code> 和 <code>"A"</code> 是不同类型的石头。

&nbsp;

示例 1：

<pre>
输入：jewels = "aA", stones = "aAAbbbb"
输出：3
</pre>

示例 2：

<pre>
输入：jewels = "z", stones = "ZZ"
输出：0
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;=&nbsp;jewels.length, stones.length &lt;= 50</code></li>
	<li><code>jewels</code> 和 <code>stones</code> 仅由英文字母组成</li>
	<li><code>jewels</code> 中的所有字符都是 唯一的</li>
</ul>