managers-with-at-least-5-direct-reports

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Database

Table: <code>Employee</code>

<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| name | varchar |
| department | varchar |
| managerId | int |
+-------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table indicates the name of an employee, their department, and the id of their manager.
If managerId is null, then the employee does not have a manager.
No employee will be the manager of themself.
</pre>

&nbsp;

Write a solution to find managers with at least five direct reports.

Return the result table in any order.

The result format is in the following example.

&nbsp;
Example 1:

<pre>
Input: 
Employee table:
+-----+-------+------------+-----------+
| id | name | department | managerId |
+-----+-------+------------+-----------+
| 101 | John | A | null |
| 102 | Dan | A | 101 |
| 103 | James | A | 101 |
| 104 | Amy | A | 101 |
| 105 | Anne | A | 101 |
| 106 | Ron | B | 101 |
+-----+-------+------------+-----------+
Output: 
+------+
| name |
+------+
| John |
+------+
</pre>

find_managers

Managers with at Least 5 Direct Reports

表:&nbsp;<code>Employee</code>

<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| name | varchar |
| department | varchar |
| managerId | int |
+-------------+---------+
id 是此表的主键（具有唯一值的列）。
该表的每一行表示雇员的名字、他们的部门和他们的经理的id。
如果managerId为空，则该员工没有经理。
没有员工会成为自己的管理者。
</pre>

&nbsp;

编写一个解决方案，找出至少有五个直接下属的经理。

以 任意顺序 返回结果表。

查询结果格式如下所示。

&nbsp;

示例 1:

<pre>
输入: 
Employee 表:
+-----+-------+------------+-----------+
| id | name | department | managerId |
+-----+-------+------------+-----------+
| 101 | John | A | Null |
| 102 | Dan | A | 101 |
| 103 | James | A | 101 |
| 104 | Amy | A | 101 |
| 105 | Anne | A | 101 |
| 106 | Ron | B | 101 |
+-----+-------+------------+-----------+
输出: 
+------+
| name |
+------+
| John |
+------+</pre>