ransom-note

java

python

python3

mysql

mssql

oraclesql

csharp

javascript

typescript

bash

swift

kotlin

dart

golang

ruby

scala

rust

racket

erlang

elixir

pythondata

postgresql

cangjie

Algorithms

Given two strings <code>ransomNote</code> and <code>magazine</code>, return <code>true</code> if <code>ransomNote</code> can be constructed by using the letters from <code>magazine</code> and <code>false</code> otherwise.

Each letter in <code>magazine</code> can only be used once in <code>ransomNote</code>.

&nbsp;
Example 1:
<pre>Input: ransomNote = "a", magazine = "b"
Output: false
</pre>Example 2:
<pre>Input: ransomNote = "aa", magazine = "ab"
Output: false
</pre>Example 3:
<pre>Input: ransomNote = "aa", magazine = "aab"
Output: true
</pre>
&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= ransomNote.length, magazine.length &lt;= 105</code></li>
	<li><code>ransomNote</code> and <code>magazine</code> consist of lowercase English letters.</li>
</ul>

canConstruct

Ransom Note

Stickers to Spell Word

stickers-to-spell-word

贴纸拼词

Find Words That Can Be Formed by Characters

find-words-that-can-be-formed-by-characters

拼写单词

Hash Table

String

Counting

给你两个字符串：<code>ransomNote</code> 和 <code>magazine</code> ，判断 <code>ransomNote</code> 能不能由 <code>magazine</code> 里面的字符构成。

如果可以，返回 <code>true</code> ；否则返回 <code>false</code> 。

<code>magazine</code> 中的每个字符只能在 <code>ransomNote</code> 中使用一次。

&nbsp;

示例 1：

<pre>
输入：ransomNote = "a", magazine = "b"
输出：false
</pre>

示例 2：

<pre>
输入：ransomNote = "aa", magazine = "ab"
输出：false
</pre>

示例 3：

<pre>
输入：ransomNote = "aa", magazine = "aab"
输出：true
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= ransomNote.length, magazine.length &lt;= 105</code></li>
	<li><code>ransomNote</code> 和 <code>magazine</code> 由小写英文字母组成</li>
</ul>