remove-linked-list-elements

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Algorithms

Given the <code>head</code> of a linked list and an integer <code>val</code>, remove all the nodes of the linked list that has <code>Node.val == val</code>, and return the new head.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2021/03/06/removelinked-list.jpg" style="width: 500px; height: 142px;" />
<pre>
Input: head = [1,2,6,3,4,5,6], val = 6
Output: [1,2,3,4,5]
</pre>

Example 2:

<pre>
Input: head = [], val = 1
Output: []
</pre>

Example 3:

<pre>
Input: head = [7,7,7,7], val = 7
Output: []
</pre>

&nbsp;
Constraints:

<ul>
	<li>The number of nodes in the list is in the range <code>[0, 104]</code>.</li>
	<li><code>1 &lt;= Node.val &lt;= 50</code></li>
	<li><code>0 &lt;= val &lt;= 50</code></li>
</ul>

removeElements

Remove Linked List Elements

Remove Element

remove-element

移除元素

Delete Node in a Linked List

delete-node-in-a-linked-list

删除链表中的节点

Delete the Middle Node of a Linked List

delete-the-middle-node-of-a-linked-list

删除链表的中间节点

Delete Nodes From Linked List Present in Array

delete-nodes-from-linked-list-present-in-array

从链表中移除在数组中存在的节点

Convert Doubly Linked List to Array I

convert-doubly-linked-list-to-array-i

将双链表转换为数组 I

Convert Doubly Linked List to Array II

convert-doubly-linked-list-to-array-ii

将双链表转换为数组 II

Recursion

Linked List

给你一个链表的头节点 <code>head</code> 和一个整数 <code>val</code> ，请你删除链表中所有满足 <code>Node.val == val</code> 的节点，并返回 新的头节点 。
 

示例 1：
<img alt="" src="https://assets.leetcode.com/uploads/2021/03/06/removelinked-list.jpg" style="width: 500px; height: 142px;" />
<pre>
输入：head = [1,2,6,3,4,5,6], val = 6
输出：[1,2,3,4,5]
</pre>

示例 2：

<pre>
输入：head = [], val = 1
输出：[]
</pre>

示例 3：

<pre>
输入：head = [7,7,7,7], val = 7
输出：[]
</pre>

 

提示：

<ul>
	<li>列表中的节点数目在范围 <code>[0, 104]</code> 内</li>
	<li><code>1 <= Node.val <= 50</code></li>
	<li><code>0 <= val <= 50</code></li>
</ul>