reverse-string-ii

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Algorithms

Given a string <code>s</code> and an integer <code>k</code>, reverse the first <code>k</code> characters for every <code>2k</code> characters counting from the start of the string.

If there are fewer than <code>k</code> characters left, reverse all of them. If there are less than <code>2k</code> but greater than or equal to <code>k</code> characters, then reverse the first <code>k</code> characters and leave the other as original.

&nbsp;
Example 1:
<pre>Input: s = "abcdefg", k = 2
Output: "bacdfeg"
</pre>Example 2:
<pre>Input: s = "abcd", k = 2
Output: "bacd"
</pre>
&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= s.length &lt;= 104</code></li>
	<li><code>s</code> consists of only lowercase English letters.</li>
	<li><code>1 &lt;= k &lt;= 104</code></li>
</ul>

reverseStr

Reverse String II

Reverse String

reverse-string

反转字符串

Reverse Words in a String III

reverse-words-in-a-string-iii

反转字符串中的单词 III

Faulty Keyboard

faulty-keyboard

故障键盘

Two Pointers

String

给定一个字符串 <code>s</code> 和一个整数 <code>k</code>，从字符串开头算起，每计数至 <code>2k</code> 个字符，就反转这 <code>2k</code> 字符中的前 <code>k</code> 个字符。

<ul>
	<li>如果剩余字符少于 <code>k</code> 个，则将剩余字符全部反转。</li>
	<li>如果剩余字符小于 <code>2k</code> 但大于或等于 <code>k</code> 个，则反转前 <code>k</code> 个字符，其余字符保持原样。</li>
</ul>

&nbsp;

示例 1：

<pre>
输入：s = "abcdefg", k = 2
输出："bacdfeg"
</pre>

示例 2：

<pre>
输入：s = "abcd", k = 2
输出："bacd"
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= s.length &lt;= 104</code></li>
	<li><code>s</code> 仅由小写英文组成</li>
	<li><code>1 &lt;= k &lt;= 104</code></li>
</ul>