reverse-words-in-a-string-iii

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Algorithms

Given a string <code>s</code>, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

&nbsp;
Example 1:

<pre>
Input: s = &quot;Let&#39;s take LeetCode contest&quot;
Output: &quot;s&#39;teL ekat edoCteeL tsetnoc&quot;
</pre>

Example 2:

<pre>
Input: s = &quot;Mr Ding&quot;
Output: &quot;rM gniD&quot;
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= s.length &lt;= 5 * 104</code></li>
	<li><code>s</code> contains printable ASCII characters.</li>
	<li><code>s</code> does not contain any leading or trailing spaces.</li>
	<li>There is at least one word in <code>s</code>.</li>
	<li>All the words in <code>s</code> are separated by a single space.</li>
</ul>

reverseWords

Reverse Words in a String III

Reverse String II

reverse-string-ii

反转字符串 II

Two Pointers

String

给定一个字符串<meta charset="UTF-8" />&nbsp;<code>s</code>&nbsp;，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序。

&nbsp;

示例 1：

<pre>
输入：s = "Let's take LeetCode contest"
输出："s'teL ekat edoCteeL tsetnoc"
</pre>

示例 2:

<pre>
输入： s = "Mr Ding"
输出："rM gniD"
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= s.length &lt;= 5 * 104</code></li>
	<li><meta charset="UTF-8" /><code>s</code>&nbsp;包含可打印的 ASCII 字符。</li>
	<li><meta charset="UTF-8" /><code>s</code>&nbsp;不包含任何开头或结尾空格。</li>
	<li><meta charset="UTF-8" /><code>s</code>&nbsp;里 至少 有一个词。</li>
	<li><meta charset="UTF-8" /><code>s</code>&nbsp;中的所有单词都用一个空格隔开。</li>
</ul>