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Algorithms

Given two strings <code>s</code> and <code>goal</code>, return <code>true</code> if and only if <code>s</code> can become <code>goal</code> after some number of shifts on <code>s</code>.

A shift on <code>s</code> consists of moving the leftmost character of <code>s</code> to the rightmost position.

<ul>
	<li>For example, if <code>s = &quot;abcde&quot;</code>, then it will be <code>&quot;bcdea&quot;</code> after one shift.</li>
</ul>

&nbsp;
Example 1:
<pre>Input: s = "abcde", goal = "cdeab"
Output: true
</pre>Example 2:
<pre>Input: s = "abcde", goal = "abced"
Output: false
</pre>
&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= s.length, goal.length &lt;= 100</code></li>
	<li><code>s</code> and <code>goal</code> consist of lowercase English letters.</li>
</ul>

rotateString

Rotate String

String

String Matching

给定两个字符串, <code>s</code>&nbsp;和&nbsp;<code>goal</code>。如果在若干次旋转操作之后，<code>s</code>&nbsp;能变成&nbsp;<code>goal</code>&nbsp;，那么返回&nbsp;<code>true</code>&nbsp;。

<code>s</code>&nbsp;的 旋转操作 就是将&nbsp;<code>s</code> 最左边的字符移动到最右边。&nbsp;

<ul>
	<li>例如, 若&nbsp;<code>s = 'abcde'</code>，在旋转一次之后结果就是<code>'bcdea'</code>&nbsp;。</li>
</ul>

&nbsp;

示例 1:

<pre>
输入: s = "abcde", goal = "cdeab"
输出: true
</pre>

示例 2:

<pre>
输入: s = "abcde", goal = "abced"
输出: false
</pre>

&nbsp;

提示:

<ul>
	<li><code>1 &lt;= s.length, goal.length &lt;= 100</code></li>
	<li><code>s</code>&nbsp;和&nbsp;<code>goal</code>&nbsp;由小写英文字母组成</li>
</ul>