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Algorithms

Given two strings <code>s</code> and <code>goal</code>, return <code>true</code> if and only if <code>s</code> can become <code>goal</code> after some number of shifts on <code>s</code>.

A shift on <code>s</code> consists of moving the leftmost character of <code>s</code> to the rightmost position.

<ul>
	<li>For example, if <code>s = &quot;abcde&quot;</code>, then it will be <code>&quot;bcdea&quot;</code> after one shift.</li>
</ul>

&nbsp;
Example 1:

<div class="example-block">
Input: s = &quot;abcde&quot;, goal = &quot;cdeab&quot;

Output: true

Explanation:

Rotating <code>s</code> to the left by 2 positions moves <code>&quot;ab&quot;</code> to the end, resulting in <code>&quot;cdeab&quot;</code>, which is equal to <code>goal</code>.
</div>

Example 2:

<div class="example-block">
Input: s = &quot;abcde&quot;, goal = &quot;abced&quot;

Output: false

Explanation:

No sequence of rotations of <code>s</code> can produce <code>&quot;abced&quot;</code>. The characters appear in a different relative order, so <code>goal</code> is not a rotation of <code>s</code>.
</div>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= s.length, goal.length &lt;= 100</code></li>
	<li><code>s</code> and <code>goal</code> consist of lowercase English letters.</li>
</ul>

rotateString

Rotate String

String

String Matching

给定两个字符串, <code>s</code>&nbsp;和&nbsp;<code>goal</code>。如果在若干次旋转操作之后，<code>s</code>&nbsp;能变成&nbsp;<code>goal</code>&nbsp;，那么返回&nbsp;<code>true</code>&nbsp;。

<code>s</code>&nbsp;的 旋转操作 就是将&nbsp;<code>s</code> 最左边的字符移动到最右边。&nbsp;

<ul>
	<li>例如, 若&nbsp;<code>s = 'abcde'</code>，在旋转一次之后结果就是<code>'bcdea'</code>&nbsp;。</li>
</ul>

&nbsp;

示例 1：

<div class="example-block">
输入： s = "abcde", goal = "cdeab"

输出： true

解释：

将 <code>s</code> 向左旋转 2 个位置，即可将 <code>"ab"</code> 移动到字符串末尾，得到 <code>"cdeab"</code>，与 <code>goal</code> 相等。
</div>

示例 2：

<div class="example-block">
输入： s = "abcde", goal = "abced"

输出： false

解释：

无论对 <code>s</code> 进行多少次旋转，都无法得到 <code>"abced"</code>。由于字符的相对顺序不同，因此 <code>goal</code> 不是 <code>s</code> 的旋转结果。
</div>

&nbsp;

提示:

<ul>
	<li><code>1 &lt;= s.length, goal.length &lt;= 100</code></li>
	<li><code>s</code>&nbsp;和&nbsp;<code>goal</code>&nbsp;由小写英文字母组成</li>
</ul>