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英文版：Cracking the Coding Interview，源自硅谷程序员的面试红宝书

LCCI

Imagine a (literal) stack of plates. If the stack gets too high, it might topple. Therefore, in real life, we would likely start a new stack when the previous stack exceeds some threshold. Implement a data structure <code>SetOfStacks</code> that mimics this.&nbsp;<code>SetOfStacks</code> should be composed of several stacks and should create a new stack once the previous one exceeds capacity. <code>SetOfStacks.push()</code> and <code>SetOfStacks.pop()</code> should behave identically to a single stack (that is, <code>pop()</code> should return the same values as it would if there were just a single stack). Follow Up: Implement a function <code>popAt(int index)</code> which performs a pop operation on a specific sub-stack.

You should delete the sub-stack when it becomes empty. <code>pop</code>, <code>popAt</code> should return -1 when there&#39;s no element to pop.

Example1:

<pre>
 Input: 
[&quot;StackOfPlates&quot;, &quot;push&quot;, &quot;push&quot;, &quot;popAt&quot;, &quot;pop&quot;, &quot;pop&quot;]
[[1], [1], [2], [1], [], []]
 Output: 
[null, null, null, 2, 1, -1]
 Explanation: 
</pre>

Example2:

<pre>
 Input: 
[&quot;StackOfPlates&quot;, &quot;push&quot;, &quot;push&quot;, &quot;push&quot;, &quot;popAt&quot;, &quot;popAt&quot;, &quot;popAt&quot;]
[[2], [1], [2], [3], [0], [0], [0]]
 Output: 
[null, null, null, null, 2, 1, 3]
</pre>

Stack of Plates LCCI

Stack

Design

Linked List

堆盘子。设想有一堆盘子，堆太高可能会倒下来。因此，在现实生活中，盘子堆到一定高度时，我们就会另外堆一堆盘子。请实现数据结构<code>SetOfStacks</code>，模拟这种行为。<code>SetOfStacks</code>应该由多个栈组成，并且在前一个栈填满时新建一个栈。此外，<code>SetOfStacks.push()</code>和<code>SetOfStacks.pop()</code>应该与普通栈的操作方法相同（也就是说，pop()返回的值，应该跟只有一个栈时的情况一样）。 进阶：实现一个<code>popAt(int index)</code>方法，根据指定的子栈，执行pop操作。

当某个栈为空时，应当删除该栈。当栈中没有元素或不存在该栈时，<code>pop</code>，<code>popAt</code>&nbsp;应返回 -1.

示例 1：

<pre>
 输入：
["StackOfPlates", "push", "push", "popAt", "pop", "pop"]
[[1], [1], [2], [1], [], []]
 输出：
[null, null, null, 2, 1, -1]
</pre>

示例 2：

<pre>
 输入：
["StackOfPlates", "push", "push", "push", "popAt", "popAt", "popAt"]
[[2], [1], [2], [3], [0], [0], [0]]
 输出：
[null, null, null, null, 2, 1, 3]
</pre>