subrectangle-queries

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Algorithms

Implement the class <code>SubrectangleQueries</code>&nbsp;which receives a <code>rows x cols</code> rectangle as a matrix of integers in the constructor and supports two methods:

1.<code>&nbsp;updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)</code>

<ul>
	<li>Updates all values with <code>newValue</code> in the subrectangle whose upper left coordinate is <code>(row1,col1)</code> and bottom right coordinate is <code>(row2,col2)</code>.</li>
</ul>

2.<code>&nbsp;getValue(int row, int col)</code>

<ul>
	<li>Returns the current value of the coordinate <code>(row,col)</code> from&nbsp;the rectangle.</li>
</ul>

&nbsp;
Example 1:

<pre>
Input
[&quot;SubrectangleQueries&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;,&quot;getValue&quot;]
[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
Output
[null,1,null,5,5,null,10,5]
Explanation
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); 
// The initial rectangle (4x3) looks like:
// 1 2 1
// 4 3 4
// 3 2 1
// 1 1 1
subrectangleQueries.getValue(0, 2); // return 1
subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);
// After this update the rectangle looks like:
// 5 5 5
// 5 5 5
// 5 5 5
// 5 5 5 
subrectangleQueries.getValue(0, 2); // return 5
subrectangleQueries.getValue(3, 1); // return 5
subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);
// After this update the rectangle looks like:
// 5 5 5
// 5 5 5
// 5 5 5
// 10 10 10 
subrectangleQueries.getValue(3, 1); // return 10
subrectangleQueries.getValue(0, 2); // return 5
</pre>

Example 2:

<pre>
Input
[&quot;SubrectangleQueries&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;]
[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
Output
[null,1,null,100,100,null,20]
Explanation
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);
subrectangleQueries.getValue(0, 0); // return 1
subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);
subrectangleQueries.getValue(0, 0); // return 100
subrectangleQueries.getValue(2, 2); // return 100
subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);
subrectangleQueries.getValue(2, 2); // return 20
</pre>

&nbsp;
Constraints:

<ul>
	<li>There will be at most <code>500</code>&nbsp;operations considering both methods:&nbsp;<code>updateSubrectangle</code> and <code>getValue</code>.</li>
	<li><code>1 &lt;= rows, cols &lt;= 100</code></li>
	<li><code>rows ==&nbsp;rectangle.length</code></li>
	<li><code>cols == rectangle[i].length</code></li>
	<li><code>0 &lt;= row1 &lt;= row2 &lt; rows</code></li>
	<li><code>0 &lt;= col1 &lt;= col2 &lt; cols</code></li>
	<li><code>1 &lt;= newValue, rectangle[i][j] &lt;= 10^9</code></li>
	<li><code>0 &lt;= row &lt; rows</code></li>
	<li><code>0 &lt;= col &lt; cols</code></li>
</ul>

Subrectangle Queries

Design

Array

Matrix

请你实现一个类&nbsp;<code>SubrectangleQueries</code>&nbsp;，它的构造函数的参数是一个 <code>rows x cols</code>&nbsp;的矩形（这里用整数矩阵表示），并支持以下两种操作：

1.<code>&nbsp;updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)</code>

<ul>
	<li>用&nbsp;<code>newValue</code>&nbsp;更新以&nbsp;<code>(row1,col1)</code>&nbsp;为左上角且以&nbsp;<code>(row2,col2)</code>&nbsp;为右下角的子矩形。</li>
</ul>

2.<code>&nbsp;getValue(int row, int col)</code>

<ul>
	<li>返回矩形中坐标 <code>(row,col)</code> 的当前值。</li>
</ul>

&nbsp;

示例 1：

<pre>输入：
[&quot;SubrectangleQueries&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;,&quot;getValue&quot;]
[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
输出：
[null,1,null,5,5,null,10,5]
解释：
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); 
// 初始的 (4x3) 矩形如下：
// 1 2 1
// 4 3 4
// 3 2 1
// 1 1 1
subrectangleQueries.getValue(0, 2); // 返回 1
subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);
// 此次更新后矩形变为：
// 5 5 5
// 5 5 5
// 5 5 5
// 5 5 5 
subrectangleQueries.getValue(0, 2); // 返回 5
subrectangleQueries.getValue(3, 1); // 返回 5
subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);
// 此次更新后矩形变为：
// 5 5 5
// 5 5 5
// 5 5 5
// 10 10 10 
subrectangleQueries.getValue(3, 1); // 返回 10
subrectangleQueries.getValue(0, 2); // 返回 5
</pre>

示例 2：

<pre>输入：
[&quot;SubrectangleQueries&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;,&quot;getValue&quot;,&quot;updateSubrectangle&quot;,&quot;getValue&quot;]
[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
输出：
[null,1,null,100,100,null,20]
解释：
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);
subrectangleQueries.getValue(0, 0); // 返回 1
subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);
subrectangleQueries.getValue(0, 0); // 返回 100
subrectangleQueries.getValue(2, 2); // 返回 100
subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);
subrectangleQueries.getValue(2, 2); // 返回 20
</pre>

&nbsp;

提示：

<ul>
	<li>最多有&nbsp;<code>500</code>&nbsp;次<code>updateSubrectangle</code> 和&nbsp;<code>getValue</code>&nbsp;操作。</li>
	<li><code>1 &lt;= rows, cols &lt;= 100</code></li>
	<li><code>rows ==&nbsp;rectangle.length</code></li>
	<li><code>cols == rectangle[i].length</code></li>
	<li><code>0 &lt;= row1 &lt;= row2 &lt; rows</code></li>
	<li><code>0 &lt;= col1 &lt;= col2 &lt; cols</code></li>
	<li><code>1 &lt;= newValue, rectangle[i][j] &lt;= 10^9</code></li>
	<li><code>0 &lt;= row &lt; rows</code></li>
	<li><code>0 &lt;= col &lt; cols</code></li>
</ul>