subtract-the-product-and-sum-of-digits-of-an-integer

java

python

python3

mysql

mssql

oraclesql

csharp

javascript

typescript

bash

swift

kotlin

dart

golang

ruby

scala

rust

racket

erlang

elixir

pythondata

postgresql

cangjie

Algorithms

Given an integer number <code>n</code>, return the difference between the product of its digits and the sum of its digits.
&nbsp;
Example 1:

<pre>
Input: n = 234
Output: 15 
Explanation: 
Product of digits = 2 * 3 * 4 = 24 
Sum of digits = 2 + 3 + 4 = 9 
Result = 24 - 9 = 15
</pre>

Example 2:

<pre>
Input: n = 4421
Output: 21
Explanation: 
Product of digits = 4 * 4 * 2 * 1 = 32 
Sum of digits = 4 + 4 + 2 + 1 = 11 
Result = 32 - 11 = 21
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= n &lt;= 10^5</code></li>
</ul>

subtractProductAndSum

Subtract the Product and Sum of Digits of an Integer

Math

给你一个整数&nbsp;<code>n</code>，请你帮忙计算并返回该整数「各位数字之积」与「各位数字之和」的差。

&nbsp;

示例 1：

<pre>输入：n = 234
输出：15 
解释：
各位数之积 = 2 * 3 * 4 = 24 
各位数之和 = 2 + 3 + 4 = 9 
结果 = 24 - 9 = 15
</pre>

示例 2：

<pre>输入：n = 4421
输出：21
解释： 
各位数之积 = 4 * 4 * 2 * 1 = 32 
各位数之和 = 4 + 4 + 2 + 1 = 11 
结果 = 32 - 11 = 21
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= n &lt;= 10^5</code></li>
</ul>