ugly-number-iii

java

python

python3

mysql

mssql

oraclesql

csharp

javascript

typescript

bash

swift

kotlin

dart

golang

ruby

scala

rust

racket

erlang

elixir

pythondata

postgresql

cangjie

Algorithms

An ugly number is a positive integer that is divisible by <code>a</code>, <code>b</code>, or <code>c</code>.

Given four integers <code>n</code>, <code>a</code>, <code>b</code>, and <code>c</code>, return the <code>nth</code> ugly number.

&nbsp;
Example 1:

<pre>
Input: n = 3, a = 2, b = 3, c = 5
Output: 4
Explanation: The ugly numbers are 2, 3, 4, 5, 6, 8, 9, 10... The 3rd is 4.
</pre>

Example 2:

<pre>
Input: n = 4, a = 2, b = 3, c = 4
Output: 6
Explanation: The ugly numbers are 2, 3, 4, 6, 8, 9, 10, 12... The 4th is 6.
</pre>

Example 3:

<pre>
Input: n = 5, a = 2, b = 11, c = 13
Output: 10
Explanation: The ugly numbers are 2, 4, 6, 8, 10, 11, 12, 13... The 5th is 10.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= n, a, b, c &lt;= 109</code></li>
	<li><code>1 &lt;= a * b * c &lt;= 1018</code></li>
	<li>It is guaranteed that the result will be in range <code>[1, 2 * 109]</code>.</li>
</ul>

nthUglyNumber

Ugly Number III

Ugly Number II

ugly-number-ii

丑数 II

Math

Binary Search

Combinatorics

Number Theory

丑数是可以被&nbsp;<code>a</code>&nbsp;或&nbsp;<code>b</code>&nbsp;或 <code>c</code>&nbsp;整除的 正整数 。

给你四个整数：<code>n</code> 、<code>a</code> 、<code>b</code> 、<code>c</code> ，请你设计一个算法来找出第&nbsp;<code>n</code>&nbsp;个丑数。

&nbsp;

示例 1：

<pre>
输入：n = 3, a = 2, b = 3, c = 5
输出：4
解释：丑数序列为 2, 3, 4, 5, 6, 8, 9, 10... 其中第 3 个是 4。</pre>

示例 2：

<pre>
输入：n = 4, a = 2, b = 3, c = 4
输出：6
解释：丑数序列为 2, 3, 4, 6, 8, 9, 10, 12... 其中第 4 个是 6。
</pre>

示例 3：

<pre>
输入：n = 5, a = 2, b = 11, c = 13
输出：10
解释：丑数序列为 2, 4, 6, 8, 10, 11, 12, 13... 其中第 5 个是 10。
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= n, a, b, c &lt;= 109</code></li>
	<li><code>1 &lt;= a * b * c &lt;= 1018</code></li>
	<li>本题结果在&nbsp;<code>[1,&nbsp;2 * 109]</code>&nbsp;的范围内</li>
</ul>