k-items-with-the-maximum-sum

java

python3

python

javascript

typescript

csharp

golang

kotlin

swift

rust

ruby

dart

scala

elixir

erlang

racket

cangjie

bash

mysql

mssql

postgresql

oraclesql

pythondata

Algorithms

There is a bag that consists of items, each item&nbsp;has a number <code>1</code>, <code>0</code>, or <code>-1</code> written on it.

You are given four non-negative integers <code>numOnes</code>, <code>numZeros</code>, <code>numNegOnes</code>, and <code>k</code>.

The bag initially contains:

<ul>
	<li><code>numOnes</code> items with <code>1</code>s written on them.</li>
	<li><code>numZeroes</code> items with <code>0</code>s written on them.</li>
	<li><code>numNegOnes</code> items with <code>-1</code>s written on them.</li>
</ul>

We want to pick exactly <code>k</code> items among the available items. Return the maximum possible sum of numbers written on the items.

&nbsp;
Example 1:

<pre>
Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2
Output: 2
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2.
It can be proven that 2 is the maximum possible sum.
</pre>

Example 2:

<pre>
Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4
Output: 3
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3.
It can be proven that 3 is the maximum possible sum.
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>0 &lt;= numOnes, numZeros, numNegOnes &lt;= 50</code></li>
	<li><code>0 &lt;= k &lt;= numOnes + numZeros + numNegOnes</code></li>
</ul>

第 338 场周赛

weekly-contest-338

kItemsWithMaximumSum

中级工程师

K Items With the Maximum Sum

Maximum Subarray

maximum-subarray

最大子数组和

Greedy

Math

袋子中装有一些物品，每个物品上都标记着数字 <code>1</code> 、<code>0</code> 或 <code>-1</code> 。

给你四个非负整数 <code>numOnes</code> 、<code>numZeros</code> 、<code>numNegOnes</code> 和 <code>k</code> 。

袋子最初包含：

<ul>
	<li><code>numOnes</code> 件标记为 <code>1</code> 的物品。</li>
	<li><code>numZeros</code> 件标记为 <code>0</code> 的物品。</li>
	<li><code>numNegOnes</code> 件标记为 <code>-1</code> 的物品。</li>
</ul>

现计划从这些物品中恰好选出 <code>k</code> 件物品。返回所有可行方案中，物品上所标记数字之和的最大值。

&nbsp;

示例 1：

<pre>
输入：numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2
输出：2
解释：袋子中的物品分别标记为 {1, 1, 1, 0, 0} 。取 2 件标记为 1 的物品，得到的数字之和为 2 。
可以证明 2 是所有可行方案中的最大值。</pre>

示例 2：

<pre>
输入：numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4
输出：3
解释：袋子中的物品分别标记为 {1, 1, 1, 0, 0} 。取 3 件标记为 1 的物品，1 件标记为 0 的物品，得到的数字之和为 3 。
可以证明 3 是所有可行方案中的最大值。
</pre>

&nbsp;

提示：

<ul>
	<li><code>0 &lt;= numOnes, numZeros, numNegOnes &lt;= 50</code></li>
	<li><code>0 &lt;= k &lt;= numOnes + numZeros + numNegOnes</code></li>
</ul>