reverse-letters-then-special-characters-in-a-string

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Algorithms

You are given a string <code>s</code> consisting of lowercase English letters and special characters.

Your task is to perform these in order:

<ul>
	<li>Reverse the lowercase letters and place them back into the positions originally occupied by letters.</li>
	<li>Reverse the special characters and place them back into the positions originally occupied by special characters.</li>
</ul>

Return the resulting string after performing the reversals.

&nbsp;
Example 1:

<div class="example-block">
Input: s = &quot;)ebc#da@f(&quot;

Output: &quot;(fad@cb#e)&quot;

Explanation:

<ul>
	<li>The letters in the string are <code>[&#39;e&#39;, &#39;b&#39;, &#39;c&#39;, &#39;d&#39;, &#39;a&#39;, &#39;f&#39;]</code>:

	<ul>
		<li>Reversing them gives <code>[&#39;f&#39;, &#39;a&#39;, &#39;d&#39;, &#39;c&#39;, &#39;b&#39;, &#39;e&#39;]</code></li>
		<li><code>s</code> becomes <code>&quot;)fad#cb@e(&quot;</code></li>
	</ul>
	</li>
	<li>​​​​​​​The special characters in the string are <code>[&#39;)&#39;, &#39;#&#39;, &#39;@&#39;, &#39;(&#39;]</code>:
	<ul>
		<li>Reversing them gives <code>[&#39;(&#39;, &#39;@&#39;, &#39;#&#39;, &#39;)&#39;]</code></li>
		<li><code>s</code> becomes <code>&quot;(fad@cb#e)&quot;</code></li>
	</ul>
	</li>
</ul>
</div>

Example 2:

<div class="example-block">
Input: s = &quot;z&quot;

Output: &quot;z&quot;

Explanation:

The string contains only one letter, and reversing it does not change the string. There are no special characters.
</div>

Example 3:

<div class="example-block">
Input: s = &quot;!@#$%^&amp;*()&quot;

Output: &quot;)(*&amp;^%$#@!&quot;

Explanation:

The string contains no letters. The string contains all special characters, so reversing the special characters reverses the whole string.
</div>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= s.length &lt;= 100</code></li>
	<li><code>s</code> consists only of lowercase English letters and the special characters in <code>&quot;!@#$%^&amp;*()&quot;</code>.</li>
</ul>

第 175 场双周赛

biweekly-contest-175

reverseByType

中级工程师

Reverse Letters Then Special Characters in a String

Reverse Only Letters

reverse-only-letters

仅仅反转字母

Two Pointers

String

Simulation

给你一个由小写英文字母和特殊字符组成的字符串 <code>s</code>。

你的任务是 按顺序 执行以下操作：

<ul>
	<li>反转小写字母，并将它们放回原来字母所占据的位置。</li>
	<li>反转特殊字符，并将它们放回原来特殊字符所占据的位置。</li>
</ul>

返回执行反转操作后的结果字符串。

&nbsp;

示例 1：

<div class="example-block">
输入： s = ")ebc#da@f("

输出： "(fad@cb#e)"

解释：

<ul>
	<li>字符串中的字母为 <code>['e', 'b', 'c', 'd', 'a', 'f']</code>：

	<ul>
		<li>反转它们得到 <code>['f', 'a', 'd', 'c', 'b', 'e']</code></li>
		<li><code>s</code> 变为 <code>")fad#cb@e("</code></li>
	</ul>
	</li>
	<li>字符串中的特殊字符为 <code>[')', '#', '@', '(']</code>：
	<ul>
		<li>反转它们得到 <code>['(', '@', '#', ')']</code></li>
		<li><code>s</code> 变为 <code>"(fad@cb#e)"</code></li>
	</ul>
	</li>
</ul>
</div>

示例 2：

<div class="example-block">
输入： s = "z"

输出： "z"

解释：

字符串仅包含一个字母，反转它不会改变字符串。没有特殊字符。
</div>

示例 3：

<div class="example-block">
输入： s = "!@#$%^&amp;*()"

输出： ")(*&amp;^%$#@!"

解释：

字符串不包含字母。字符串全部由特殊字符组成，因此反转特殊字符即反转整个字符串。
</div>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= s.length &lt;= 100</code></li>
	<li><code>s</code> 仅由小写英文字母和 <code>"!@#$%^&amp;*()"</code> 中的特殊字符组成。</li>
</ul>